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TreeLayout (Read 11113 times)

Silvia88 Full Member Offline I Love MindFusion! Posts: 121 Joined: Aug 31^st, 2015	TreeLayout Sep 24^th, 2015 at 1:40pm	Print Post
	Hi, how can I select the nodes that must partecipate in a treeLayout? I want to create a TreeLayout among a specified set of nodes.


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Stoyo God Member Offline MindFusion support Posts: 13230 Joined: Jul 20^th, 2005	Re: TreeLayout Reply #1 - Sep 24^th, 2015 at 1:58pm	Print Post
	Hi, You can pass diagram.getSelection().getItems() to arrange(DiagramItemList) overload if user will also select the links. Otherwise you will have to loop over all selected nodes and collect the nodes and links programmatically. I hope that helps, Stoyan


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Silvia88 Full Member Offline I Love MindFusion! Posts: 121 Joined: Aug 31^st, 2015	Re: TreeLayout Reply #2 - Sep 24^th, 2015 at 2:06pm	Print Post
	Sorry but it doesn't work, because method arrange wants a Diagram and not a DiagramItemList


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Stoyo God Member Offline MindFusion support Posts: 13230 Joined: Jul 20^th, 2005	Re: TreeLayout Reply #3 - Sep 24^th, 2015 at 4:53pm	Print Post
	Ok, this overload is not available for TreeLayout. It only lets you arrange subsets of the tree by specifying the branch' root node via TreeLayout.setRoot method. Depending on what you are trying to do: - call arrange from a loop, each iteration using next selected node as a root - or find the common ancestor of all selected nodes and set it as a root, calling arrange a single time.


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Silvia88 Full Member Offline I Love MindFusion! Posts: 121 Joined: Aug 31^st, 2015	Re: TreeLayout Reply #4 - Sep 25^th, 2015 at 11:44am	Print Post
	Ok, thank you very much The problem is that I have a list of nodes and I want to create a tree(or something similar) only among these nodes, but if I use a tree layout it takes all nodes present in the diagram while I want only the nodes belonging to the list to be part of the tree. I have the nodes in this list: List<ShapeNode> treeNodes where the node at the second position must be the root, how can I create a treeLayout only among these nodes?


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Stoyo God Member Offline MindFusion support Posts: 13230 Joined: Jul 20^th, 2005	Re: TreeLayout Reply #5 - Sep 25^th, 2015 at 3:51pm	Print Post
	Set that second node from list as TreeLayout.Root, and also enable the KeepRootPosition property so the layout does not move it, but only the children. If the nodes are already connected with links, TreeLayout should arrange them under the root then without modifying the rest of the tree. If there are child nodes that should not be arranged, you could set their IgnoreLayout property. I hope that helps, Stoyan


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Silvia88 Full Member Offline I Love MindFusion! Posts: 121 Joined: Aug 31^st, 2015	Re: TreeLayout Reply #6 - Sep 25^th, 2015 at 4:09pm	Print Post
	I did it but it doesn't work, by setting ignoreLayout to true it simply draws it in a different way but still connect the node that should be ignored, I want the node that should be ignored to be connected to the root of the layout and not to other node.


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Silvia88 Full Member Offline I Love MindFusion! Posts: 121 Joined: Aug 31^st, 2015	Re: TreeLayout Reply #7 - Sep 25^th, 2015 at 5:13pm	Print Post
	Hi, I solved the problem, I manage it in a different way and now it does what I want, thank you anyway


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Silvia88 Full Member Offline I Love MindFusion! Posts: 121 Joined: Aug 31^st, 2015	Re: TreeLayout Reply #8 - Sep 28^th, 2015 at 1:54pm	Print Post
	Hi, sorry but I have another problem with tree layout, I have something like in the attachment, I called method setText on the bigger link but it wrote the text, (Text) in the example, in rect1 while I want to write it in the middle of the bigger link.

	ex2.png ( 5 KB \| 146 Downloads )
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Stoyo God Member Offline MindFusion support Posts: 13230 Joined: Jul 20^th, 2005	Re: TreeLayout Reply #9 - Sep 29^th, 2015 at 9:11am	Print Post
	Hi, If that arrow shape is a DiagramLink instance, try setting a different LinkTextStyle via DiagramLink.setTextStyle method, or alternatively use LinkLabel objects, which give you more control over positioning. If it's a ShapeNode with a custom shape, you might have specified a text region that's above the main graphics. In such case remove the text region definition from Shape constructor and the control should use the graphics outline for text too. I hope that helps, Stoyan


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Silvia88 Full Member Offline I Love MindFusion! Posts: 121 Joined: Aug 31^st, 2015	Re: TreeLayout Reply #10 - Sep 29^th, 2015 at 9:57am	Print Post
	Ok, thank you very much, I used LinkLabel and it works. But is there a way to take the length of the arrow headShape? Because I want to put the label just under the arraow, like this:

	ex.png ( 2 KB \| 139 Downloads )
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Stoyo God Member Offline MindFusion support Posts: 13230 Joined: Jul 20^th, 2005	Re: TreeLayout Reply #11 - Sep 29^th, 2015 at 3:25pm	Print Post
	Call the getHeadShapeSize method to find the default size, or setHeadShapeSize to set your own size. I hope that helps, Stoyan


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Silvia88 Full Member Offline I Love MindFusion! Posts: 121 Joined: Aug 31^st, 2015	Re: TreeLayout Reply #12 - Sep 29^th, 2015 at 3:36pm	Print Post
	Thank you very much


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Silvia88 Full Member Offline I Love MindFusion! Posts: 121 Joined: Aug 31^st, 2015	Re: TreeLayout Reply #13 - Sep 30^th, 2015 at 5:42pm	Print Post
	Hi, is there a way to know if a node belong to a TreeLayout? Because I need to know it when I load the diagram from a saved file


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Stoyo God Member Offline MindFusion support Posts: 13230 Joined: Jul 20^th, 2005	Re: TreeLayout Reply #14 - Sep 30^th, 2015 at 6:19pm	Print Post
	Hi, There's nothing built-in to keep track of nodes processed by TreeLayout. You could mark them as processed by setting their Tag property from some recursive function you call starting with TreeLayout.Root node: Code void markProcessed(DiagramNode node) { node.setTag(true); for (DiagramLink link : node.getOutgoingLinks()) // or incoming depending on tree direction { markProcessed(link.getDestination()); // or getOrigin } } I hope that helps, Stoyan


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