Hi Stoyan,
How do I determine which node was right-clicked? The right-clicked node is not necessarily the Diagram.ActiveItem.

I have a ContextMenuStrip on my DiagramView but want to change the content of the menustrip depending on the node that right-clicked on.

Many thanks,
Johan

Hi Stoyan,
Thanks for the reply. The problem is I'm already handling the contextMenuStrip_ItemClicked event. It is in this event that I need to get the node that was right-clicked. There isn't maybe a property to indicate which node had the "mouse over", something similar to ActiveItem? When one moves the mouse over a Node the display of the Node changes so I'm sure there must be a way?

Another option would be to assign the contectMenuStrip to a Node but I couldn't find a way to do this so I had to assigned it to the DiagramView.


Many thanks,
Johan

Hi Stoyan,
I'm now using the NodeClicked event and store the node in a class variable for later use. This is working great but because the contextMenuStrip_ItemClicked event fires before the NodeClicked event I now have to programmatically show the contextMenuStrip in the NodeClicked event.

I want to show the menuStrip at the same position as the node but I have tried everything to get the correct X and Y coordinates but my menuStrip never opens at the correct place. How do I get the correct point?

This code gets it very close but not 100%:
       private void diagramProcessFlow_NodeClicked(object sender, NodeEventArgs e)
       {
           // Make sure we have clicked a Shape Node and display the menu
           if (e.MouseButton == MouseButton.Right && (e.Node is ShapeNode))
           {
               clickedNode = e.Node;
               contextMenuStripFeatures.Show(pnlProcessFlow, new Point(Convert.ToInt32(e.Node.Bounds.X), Convert.ToInt32(e.Node.Bounds.Y)));
           }
       }

Thanks,
Johan