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Normal Topic Link between overlapping nodes (Read 1965 times)
Anshul
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Link between overlapping nodes
Oct 20th, 2009 at 10:32am
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Hi Stoyan,

I have two nodes in the diagram with link between them.

When two nodes are not overlapping,link between two nodes is straight arrow with ends just touching both nodes.

But when nodes are overlapping,link overlaps over the two nodes.

But I want that link should not overlap any node. It can be represented in the form of curved arrow  or by dot ,in case nodes are overlapping.

I am sending image for the same,have a look into that.

Regards,
Anshul.
  
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Stoyo
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Re: Link between overlapping nodes
Reply #1 - Oct 20th, 2009 at 3:56pm
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You could do something like:

Code
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DiagramNode node1 = link.Origin;
DiagramNode node2 = link.Destination;
if (node1.Bounds.IntersectsWith(node2.Bounds))
{
	link.ControlPoints[0] = GetTopCenter(node1);
	link.ControlPoints[link.ControlPoints - 1] = GetTopCenter(node2);
	link.Style = LinkStyle.Bezier;
	link.Route();
}


I hope that helps,
Stoyan
  
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Anshul
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Re: Link between overlapping nodes
Reply #2 - Oct 23rd, 2009 at 9:05am
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Hi Stoyan,

Its not working as expected.

And also in addition to this,

When 2 nodes are connected and if there is a third node inbetween them - the link should not go through that node.

Please suggest for this.

Regards,
Anshul
  
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Stoyo
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Re: Link between overlapping nodes
Reply #3 - Oct 27th, 2009 at 2:01pm
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Hi,

Ok, first change the style and then call Route(), otherwise the Style setter moves the points back to the node centers when the nodes intersect.

Code
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Point GetTopCenter(DiagramNode node)
{
	Rect r = node.Bounds;
	return new Point(r.X + r.Width / 2, r.Y);
}

private void OnLinkCreated(object sender, LinkEventArgs e)
{
	var link = e.Link;
	DiagramNode node1 = link.Origin;
	DiagramNode node2 = link.Destination;
	if (node1.Bounds.IntersectsWith(node2.Bounds))
	{
		link.Style = LinkStyle.Bezier;
		link.ControlPoints[0] = GetTopCenter(node1);
		link.ControlPoints[link.ControlPoints.Count - 1] = GetTopCenter(node2);
		link.Route();
	}
}


I hope that helps,
Stoyan
  
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